Math Student Help

Cass McCombs plays Subtraction at Spreckels Theatre in San Diego, CA on 4/26/07 before Arcade Fire.

Duration : 0:2:35

(more…)

An explanation of the expanded method of subtraction with examples.
Decomposition is explained and informal jottings are demonstrated.

Duration : 0:4:45

(more…)

Subtraction and division are inverse operations to addition and multiplication. Part of a series on the foundations of mathematics

Duration : 0:10:7

(more…)

Access full lesson containing this video at: http://www.yourteacher.com/prealgebra/subtractionequations.php Students learn to solve one-step subtraction equations. For example, to solve z - 3 = 16, add 3 to both sides of the equation, to get z = 19. Next, check the solution by substituting a 19 back into the original equation, to get (19) — 3 = 16, which is a true statement, so the solution checks.

Duration : 0:1:29

(more…)

http://www.timbedley.com A cool little trick that will make your life complete. 20-year veteran elementary school teacher Tim Bedley shows how adding and subtracting positive and negative numbers can be a painless experience.
For more teaching ideas and educational videos please visit http://www.timbedley.com

Duration : 0:9:17

(more…)

Duration : 0:3:8

(more…)

Access full lesson containing this video at: http://www.yourteacher.com/prealgebra/subtractingdecimals.php Students learn to subtract decimals by first lining up the decimal points, then subtracting the numbers by column. For example, to subtract 9.514 — 1.6, first line up the decimal points, then subtract the digits the thousandths column, to get 4 - 0, or 4, then subtract the digits in the hundredths column, to get 1 — 0, or 1, then subtract the digits in units column, by borrowing a 1 from the 9 in the units column (which leaves an 8 in the units column), to get 15 — 6, or 9, then subtract the digits in the units column, to get 8 — 1, or 7. So 9.514 — 1.6 = 7.914.

Duration : 0:1:32

(more…)

Access full lesson containing this video at: http://www.yourteacher.com/prealgebra/subtractingmixednumbers.php Students learn to subtract mixed numbers by first subtracting the fractions, then subtracting the whole numbers. For example, to subtract 6 1/3 - 4 2/3, first subtract 1/3 � 2/3. However, notice that 1/3 � 2/3 equals a negative fraction. In this situation, the first fraction, 6 1/3, can be rewritten as 5 + 1 1/3, or 5 + 4/3, or 5 4/3. Therefore, the original problem, 6 1/3 - 4 2/3, can be rewritten as 5 4/3 - 4 2/3. Now, subtract the fractions, 4/3 � 2/3, to get 2/3, and subtract the whole numbers, 5 �4, to get 1. So 5 4/3 - 4 2/3 = 1 2/3. Note that some of the problems in this lesson also require the student to find a common denominator for the fractions. For example, 8 5/16 - 1 1/8.

Duration : 0:1:35

(more…)

Access full lesson containing this video at: http://www.yourteacher.com/prealgebra/subtractingwholenumbers.php Students learn to subtract numbers with two or more digits, such as 985 - 47. The first step is to line up the numbers vertically so that the units digits are in the same column. Next, subtract the units digits, the tens digits, and the hundreds digits. When subtracting the units digits, notice that it is not possible to subtract 7 ones from 5 ones, so 1 ten must be borrowed from the tens column, leaving 7 tens and 15 ones. Now, subtracting the units digits, 15 - 7 = 8, subtracting the tens digits, 7 - 4 = 3, and subtracting the hundreds digits, 9 - 0 = 9. So 985 - 47 = 938. Note that the answer to a subtraction problem is called the difference, so the difference of 985 - 47 is 938.

Duration : 0:1:25

(more…)

Access full lesson containing this video at: http://www.yourteacher.com/algebra1/subtractingrationalexpressions.php Students learn that when subtracting rational expressions, the first step is to change the minus sign between the terms to a plus sign, and change all the signs across the numerator of the following term. Next, factor each of the denominators, if possible, then give each term a common denominator by multiplying the numerator and denominator of each term by the appropriate value. Next, add across the numerators and keep the denominators the same. Finally, factor the resulting numerator, if possible, to determine if the rational expression can be reduced.

Duration : 0:2:41

(more…)