Math Student Help

Algebra Word Problem: Work. This lesson is appropriate for any algebra 1 or Algebra 2 student

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Algebra Word Problem: Inverse Variation. These problems are appropriate for a high school algebra 1 or algebra 2 student … (more)

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Algebra Word Problem: Investments, This video is appropriate for students in Algebra 1 or 2

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An alternative way to multiply, which is liable to amaze and baffle you at the same time. Robin Wilson, Gresham Professor of Geometry, explains what is sometimes called ‘Russian’ or ‘Egyptian’ multiplication.

This is the eighth part of ‘A Millennium of Mathematical Puzzles’.
The full lecture is available (in 24 parts) here on YouTube, or it can be downloaded (like all of our lectures) in its complete form from the Gresham College website, in video, audio or text formats:
http://www.gresham.ac.uk

Gresham College has been giving free public lectures since 1597. This tradition continues today with all of our five or so public lectures a week being made available for free download from our website.

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YourTeacher.com ( http://www.yourteacher.com ) offers over 1000 online math lessons with printable math worksheets, video examples, interactive practice, multiple-choice self-tests, and much more!

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Solving a Mixture problem with Algebra

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A Complete Partial Fractions Problem! For more free math videos, visit http://JustMathTutoring.com

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Access full lesson containing this video at: http://www.yourteacher.com/geometry/306090triangles.php Students are asked to solve advanced problems using the 45°-45°-90° and 30°-60°-90° triangle formulas, such as finding the missing parts of a rhombus, a trapezoid, or an equilateral triangle.

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Access full lesson containing this video at: http://www.yourteacher.com/geometry/pythagoreantheorem.php Students learn the Pythagorean Theorem, which states that the sum of the squares of the lengths of the legs of a right triangle is equal to the square of the length of the hypotenuse, or a^2 + b^2 = c^2. Students are then asked to find missing side lengths of right triangles using the Pythagorean Theorem.

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