Comments on: How do you solve fractions equations by adding and subtracting?

By: Wile E.

Wile E. — Sun, 20 Dec 2009 02:25:59 +0000

k + 3 3/4 = 5 2/3 - 1 1/3
k + 15/4 = 17/3 - 4/3…………(Convert proper fractions to improper fractions)
k = 17/3 - 4/3 - 15/4………….(Subtract 15/4 from both sides)
12k = 204/3 - 48/3 - 180/4….(Multiply both sides by 12, the LCD)
12k = 68 - 16 - 45…………….(Simplify fractions)
12k = 7…………………………(Combine like terms)
k = 7/12………………………..(Divide both sides by 12)
¯¯¯¯¯¯¯
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By: Erik

Erik — Sun, 20 Dec 2009 02:04:59 +0000

find a common denominator;
k+3 3/4=4 1/3 change to an improper fraction
k+15/4=13/3 common denominator is 12 so multiply 15/4 by 3 and 13/3 by 4
K+45/12=52/12
subtract 45/12 from both sides
K=12/12 or ONE
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too many math classes

By: [Last]_Demon

[Last]_Demon — Sun, 20 Dec 2009 01:23:59 +0000

I THINK I KNOW THE ASNWER FOR YOUR QUESTION [ 3K 3/4= 4 1/3 ]
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By: Zylo

Zylo — Sun, 20 Dec 2009 00:52:59 +0000

Start with the part you have all the numbers for. 5 2/3 - 1 1/3 obviously equals 4 1/3. So, the only other number you have is 3 3/4. Thus, subtract 3 3/4 from 4 1/3. Find the least common factor of the fractions and change it so you have 4 4/12 - 3 9/12. Then it’s simple math, normal subtraction, and leaves you with 7/12.
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By: Don

Don — Sun, 20 Dec 2009 00:27:59 +0000

I understand the problem is

k + 3 and 3/4 = 5 and 2/3 - 1 and 1/3

Change the mixed fractions into

k + 15/4 = 17/3 - 4/3

k + 15/4 = 13/3

k = 13/3 - 15/4

k = 7/12

Have a good day!
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