How do you solve fractions equations by adding and subtracting?
i have so much hard times in pre-algebra and i don’t know how to solve fractions equations addition and subtraction.the problem is k+3 3/4=5 2/3-1 1/3.the problem is i don’t know how to solve it!
I understand the problem is
k + 3 and 3/4 = 5 and 2/3 - 1 and 1/3
Change the mixed fractions into
k + 15/4 = 17/3 - 4/3
k + 15/4 = 13/3
k = 13/3 - 15/4
k = 7/12
Have a good day!
December 19th, 2009 at 7:27 pm
I understand the problem is
k + 3 and 3/4 = 5 and 2/3 - 1 and 1/3
Change the mixed fractions into
k + 15/4 = 17/3 - 4/3
k + 15/4 = 13/3
k = 13/3 - 15/4
k = 7/12
Have a good day!
References :
December 19th, 2009 at 7:52 pm
Start with the part you have all the numbers for. 5 2/3 - 1 1/3 obviously equals 4 1/3. So, the only other number you have is 3 3/4. Thus, subtract 3 3/4 from 4 1/3. Find the least common factor of the fractions and change it so you have 4 4/12 - 3 9/12. Then it’s simple math, normal subtraction, and leaves you with 7/12.
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December 19th, 2009 at 8:23 pm
I THINK I KNOW THE ASNWER FOR YOUR QUESTION [ 3K 3/4= 4 1/3 ]
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December 19th, 2009 at 9:04 pm
find a common denominator;
k+3 3/4=4 1/3 change to an improper fraction
k+15/4=13/3 common denominator is 12 so multiply 15/4 by 3 and 13/3 by 4
K+45/12=52/12
subtract 45/12 from both sides
K=12/12 or ONE
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too many math classes
December 19th, 2009 at 9:25 pm
k + 3 3/4 = 5 2/3 - 1 1/3
k + 15/4 = 17/3 - 4/3…………(Convert proper fractions to improper fractions)
k = 17/3 - 4/3 - 15/4………….(Subtract 15/4 from both sides)
12k = 204/3 - 48/3 - 180/4….(Multiply both sides by 12, the LCD)
12k = 68 - 16 - 45…………….(Simplify fractions)
12k = 7…………………………(Combine like terms)
k = 7/12………………………..(Divide both sides by 12)
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