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	<title>Comments on: How do you solve a difference quotient equation with fractions?  Finding the common denominator?</title>
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	<description>Let us help you add it up!</description>
	<pubDate>Mon, 21 May 2012 12:11:50 +0000</pubDate>
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		<title>By: Prof del C</title>
		<link>http://www.mathstudenthelp.info/fractions/how-do-you-solve-a-difference-quotient-equation-with-fractions-finding-the-common-denominator/comment-page-1#comment-7003</link>
		<dc:creator>Prof del C</dc:creator>
		<pubDate>Sun, 03 Jan 2010 03:33:59 +0000</pubDate>
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		<description>Where are those fractions in the numerator?  I don't understand what you want.  When you have compound fractions, of the sort:

[1/(x + h + 3) - 1/(x + 3)] / h, that last h is a factor of the denominator you get up above in the numerator for the final fration:

[x + 3 - x - 3 - h] / h(x + 3)(x + h + 3)...in general, (A/B)/h = A / Bh&lt;br&gt;&lt;b&gt;References : &lt;/b&gt;&lt;br&gt;</description>
		<content:encoded><![CDATA[<p>Where are those fractions in the numerator?  I don&#8217;t understand what you want.  When you have compound fractions, of the sort:</p>
<p>[1/(x + h + 3) - 1/(x + 3)] / h, that last h is a factor of the denominator you get up above in the numerator for the final fration:</p>
<p>[x + 3 - x - 3 - h] / h(x + 3)(x + h + 3)&#8230;in general, (A/B)/h = A / Bh<br /><b>References : </b></p>
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