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How do you solve a difference quotient equation with fractions? Finding the common denominator?

I understand how to do difference quotient equations, however, I am stuck on getting a common denominator in order to solve an equation with fractions in the numerator. Here are some examples, the form used is f(x + h)- f(x) / h.

ex.
a. y = 1 / 3x + 1, x = 1

b. y = -2 / x + 4, x = 2

Any help would be appreciated!

Where are those fractions in the numerator? I don’t understand what you want. When you have compound fractions, of the sort:

[1/(x + h + 3) - 1/(x + 3)] / h, that last h is a factor of the denominator you get up above in the numerator for the final fration:

[x + 3 - x - 3 - h] / h(x + 3)(x + h + 3)…in general, (A/B)/h = A / Bh

This entry was posted on Saturday, January 2nd, 2010 at 5:12 pm and is filed under fractions. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

One Response to “How do you solve a difference quotient equation with fractions? Finding the common denominator?”

  1. Prof del C Says:
    January 2nd, 2010 at 10:33 pm

    Where are those fractions in the numerator? I don’t understand what you want. When you have compound fractions, of the sort:

    [1/(x + h + 3) - 1/(x + 3)] / h, that last h is a factor of the denominator you get up above in the numerator for the final fration:

    [x + 3 - x - 3 - h] / h(x + 3)(x + h + 3)…in general, (A/B)/h = A / Bh
    References :

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