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Addition…?

Add. Simplify, if possible.

3 ……. 1
—– + —–
4z^3 . 6z^2

Note: those are fractions. I put the dots to keep the numbers from running together.

Thanks!

The hardest part is getting the least common denominator. In your case, 12 as a number is the LCM of 4 and 6. Then, you also need the most, or highest power of, number of z’s. In the first fraction, we have 3. So, the LCD is 12z^3. Now, on top you most multiply by whatever you seemingly "added" to the bottom. For the one on the left you need a 3 and the one on the right you need a 2z.

Therefore, you end up with (9+2z)/(12z^3). In this case, you can not simplify at all!

This entry was posted on Tuesday, October 6th, 2009 at 4:14 pm and is filed under addition. You can follow any responses to this entry through the RSS 2.0 feed. You can leave a response, or trackback from your own site.

4 Responses to “Addition…?”

  1. Qwerty Q Says:
    October 6th, 2009 at 9:31 pm

    remember, addition and subtraction need you to make the denominator the same. but whatever you do to the denominator, you have to do to the numerator too.

    so:

    3 x 3……………………1 x 2
    ________………+….________
    (4z^3) x 3……………..(6x^2) x 2

    ….9………………………….2
    _____………+……….._______
    12z^3…………………….12z^2

    the denominators need to be balanced, then you can simply add the numerators.
    i don’t think it can get any more simplified than this.
    References :

  2. Cameron Says:
    October 6th, 2009 at 10:10 pm

    The hardest part is getting the least common denominator. In your case, 12 as a number is the LCM of 4 and 6. Then, you also need the most, or highest power of, number of z’s. In the first fraction, we have 3. So, the LCD is 12z^3. Now, on top you most multiply by whatever you seemingly "added" to the bottom. For the one on the left you need a 3 and the one on the right you need a 2z.

    Therefore, you end up with (9+2z)/(12z^3). In this case, you can not simplify at all!
    References :

  3. The Game Says:
    October 6th, 2009 at 10:59 pm

    what??
    References :

  4. Sean Says:
    October 6th, 2009 at 11:22 pm

    3/(4z^3) + 1/(6z^2)

    = [3*3 + 2z]/[12z^3]

    = [9+2z]/[12z^3]

    It is brought to a common denominator, that is to say 12z^3, but I am not sure about being simplified.
    References :

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